With an R-410A condensing pressure of 397 psig and a liquid line temperature of 108°F, what is the subcooling temperature?

To determine the subcooling temperature, you first need to identify the saturation temperature corresponding to the condensing pressure of 397 psig. When working with refrigerants like R-410A, you can refer to a pressure-temperature chart specifically for R-410A to find the saturation temperature at that pressure.

For R-410A, a condensing pressure of 397 psig corresponds to a saturation temperature of approximately 108°F. This means that at this pressure, the refrigerant begins to condense into liquid at this temperature.

Next, to calculate the subcooling temperature, you subtract the saturation temperature from the actual liquid line temperature. In this case, the liquid line temperature is also 108°F. The formula for calculating subcooling is:

Subcooling = Liquid Line Temperature - Saturation Temperature

Substituting the values we have:

Subcooling = 108°F - 108°F = 0°F.

However, it seems there may be a misunderstanding in the options provided. The calculation needs to also consider common acceptable limits for subcooling. Subcooling typically should show a positive value, and in common practice, operational and design ranges often expect an ideal subcooling range.

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